# A gas at constant volume has 25 J of heat added to it. What is the work done by the gas?

Sep 11, 2017

$25$ joule

#### Explanation:

$\Delta U = q + w$
now volume is also constant,therefore,initial and final temperatures are also same .

Threrefore,

$\Delta U = 0$; $q = - w$

Hence 25 joule. Relatively you apply sign convention.