# A gas has a volume of 2000 mL at -253 °C and a pressure of 101.3 kPa. What will be the new volume when the temperature is changed to -233 °C and the pressure is changed to 198.5 kPa?

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$, V_2 ~=2.5*L
We use $\text{degrees Kelvin}$, and so ${V}_{2} = \frac{{P}_{1} \cdot {V}_{1} \cdot {T}_{2}}{{P}_{2} \cdot {T}_{1}}$
$= \frac{101.3 \cdot k P a \times 2000 \cdot m L \times 50 \cdot K}{198.5 \cdot k P a \times 20 \cdot K}$
=??mL