Question

A gas has a volume of 3.3 L at 25°C and 1.3 atm; at what temperature would the gas occupy 2.5 L at 1 atm?

Answer 1

174 K

Explanation:

`P_1V_1 / T_1 = P_2V_2 / T_2`.

`T_2 = (P_2V_2 T_1)//(P_1 V_1`)

`T_2` =(1.0 atm ) (2.5 L) `298 K` // 1.3 atm x 3.3 L

`T_2` = 745 atm L K // 4.29 L atm

`T_2` = 174 K