# A gas has a volume of 3.3 L at 25°C and 1.3 atm; at what temperature would the gas occupy 2.5 L at 1 atm?

Apr 18, 2016

174 K

#### Explanation:

${P}_{1} {V}_{1} / {T}_{1} = {P}_{2} {V}_{2} / {T}_{2}$.

T_2 = (P_2V_2 T_1)//(P_1 V_1)

${T}_{2}$ =(1.0 atm ) (2.5 L) $298 K$ // 1.3 atm x 3.3 L

${T}_{2}$ = 745 atm L K // 4.29 L atm

${T}_{2}$ = 174 K