A gas mixture contains 1.19 g #N_2# and 0.79 g #O_2# in a 1.60-L container at 25 deg C. How do you calculate the mole fraction of #N_2#?

1 Answer
Dec 10, 2016

Answer:

#chi_"dinitrogen"# #=# #0.64#

Explanation:

#chi_i=(n_i)/(n_"total")#.

Now #n_"total"=(1.19*g)/(28.01*g*mol^-1)+(0.79*g)/(32.00*g*mol^-1)#

#=6.67xx10^-2*mol#

And #chi_"dinitrogen"# #=# #((1.19*g)/(28.01*g*mol^-1))/(6.67xx10^-2*mol)=0.64#.

Given that it is a binary system, what is #chi_"dioxygen"?#

Note that the information given with respect to #"volume"# and #"temperature"# was included to distract you.