# A gas stream containing 45wt% butane and 55wt% pentane is subjected to heating from 180K to 260K at constant pressure. calculate the required heat input per kg of this mixture?

##
neglecting changes in kinetic and potential energies.

neglecting changes in kinetic and potential energies.

##### 1 Answer

#### Answer:

The required heat input is 184 kJ/kg.

#### Explanation:

Assume that we have 1 kg of the mixture.

Then we have 450 g of butane and 550 g of pentane.

**Step 1. Calculate the heat input for the butane**

Butane is a liquid between 180 K and 260 K.

The formula for the quantity of heat

#color(blue)(bar(ul(|color(white)(a/a)q = mC_text(s)ΔTcolor(white)(a/a)|)))" "#

where

In this problem,

The first task is to convert the mass of the butane to moles.

Now we can determine the quantity of heat needed.

**Step 2. Calculate the heat input for the pentane**

Pentane is a liquid between 180 K and 260 K.

Here,

We must convert the mass of the pentane to moles.

Now we can determine the quantity of heat needed.

**Step 3. Calculate the total heat required**