A gas tank has a volume of 28.1m^3 and a pressure of 18.4atm. The temperature of the gas is 32ºC. What is the Celsius temperature if the pressure changes to 22.7 atm?

Whats the gas law, and formula? And also how do i solve this?

1 Answer
Phiri
May 3, 2018

#"39.5°C"#

Explanation:

The Combined Gas Law states that #(P_1V_1)/T_1 = (P_2V_2)/T_2#.

#P# = Pressure
#V# = Volume
#T# = Temperature

Since we're using a gas tank and it isn't specified, I'm going to assume the Volume remains constant, so we can eliminate the Vs, giving us #P_1/T_1 = P_2/T_2#.

Plugging in values:

#"18.4atm"/"32°C" = "22.7atm"/T_2#

We need to isolate the #T_2#, so we'll cross multiply and isolate the value.

#T_2"18.4atm" = "22.7 atm * 32°C"#

#T_2 = ("22.7 atm * 32°C")/"18.4atm"#

Now let's simplify the equation. Our atm's cancel, giving us:

#T_2 = ("22.7 * 32°C")/"18.4"#

After calculating the values and applying sig figs (3 sig figs), we are given #"39.5°C"#

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