A gas with a volume of #3.00 x 10^2# mL at 150.0 degrees C is heated until its volume is #6.00 X 10^2# mL. What is the new temperature of the gas if the pressure remains constant during the heating process?

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Answer 1 · 2017-06-04T08:05:26

We use old Charles' Law, #VpropT#; units of #"absolute temperature"# must be used, #0# #""^@C=273.15*K#.

We use old Charles' Law, which states that at constant pressure, and a given quantity of gas, volume varies with temperature.........i.e. #VpropT#.

And thus #V=kT#. And if we solve for #k#, we gets the relationship....

#V_1/T_1=V_2/T_2# for a given quantity of gas.......

#T_2=(V_2xxT_1)/V_1#, #"absolute temperature"# is used......

#=(600*mLxx423.15*K)/(300*mL)=846.3*K#. Can you convert this temperature to #""^@C#?