# A gas with a volume of 3.00 x 10^2 mL at 150.0 degrees C is heated until its volume is 6.00 X 10^2 mL. What is the new temperature of the gas if the pressure remains constant during the heating process?

Jun 4, 2017

We use old Charles' Law, $V \propto T$; units of $\text{absolute temperature}$ must be used, $0$ ""^@C=273.15*K.

#### Explanation:

We use old Charles' Law, which states that at constant pressure, and a given quantity of gas, volume varies with temperature.........i.e. $V \propto T$.

And thus $V = k T$. And if we solve for $k$, we gets the relationship....

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$ for a given quantity of gas.......

${T}_{2} = \frac{{V}_{2} \times {T}_{1}}{V} _ 1$, $\text{absolute temperature}$ is used......

$= \frac{600 \cdot m L \times 423.15 \cdot K}{300 \cdot m L} = 846.3 \cdot K$. Can you convert this temperature to ""^@C?