A generator produce 100kwatt power at a potential difference of 10 KV the power transmitted through cable of total resistance 5 ohm how much power dissipated in the cables?

1 Answer
chandramohanPanakkal · Stefan V.
Jul 31, 2018

#"500 watts"#

Explanation:

#"voltage" xx "current" = "power"#.

Here

  • #"voltage" \ = \ "10,000 volts"#
  • #"power" \ = \ "100,000 watts"#

So

#"current" = "100,000 W"/"10,000 V" = "10 A"#

Now

#"power loss" = I^2xx R" "# #["current squared" xx "resistance"]#

So

#"power loss" = ("10 A")^2 xx 5 \ Omega = "500 W"#.

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