# A generator produce 100kwatt power at a potential difference of 10 KV the power transmitted through cable of total resistance 5 ohm how much power dissipated in the cables?

Jul 31, 2018

$\text{500 watts}$

#### Explanation:

$\text{voltage" xx "current" = "power}$.

Here

• $\text{voltage" \ = \ "10,000 volts}$
• $\text{power" \ = \ "100,000 watts}$

So

$\text{current" = "100,000 W"/"10,000 V" = "10 A}$

Now

$\text{power loss" = I^2xx R" }$ $\left[\text{current squared" xx "resistance}\right]$

So

$\text{power loss" = ("10 A")^2 xx 5 \ Omega = "500 W}$.