A geometric sequence is defined by the explicit formula $a_n = 3(-5)^(n-1)$ , what is the recursive formula for the nth term of this sequence?

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Answer 1 · 2017-01-05T21:07:17

$a_1=3; a_(n+1)=a_n(-5)$

The first term ( $a_1$ ) is 3.

The second one ( $a_2$ ) is obtained by multiplyng $3*(-5)$

The third one ( $a_3$ ) by multiplying $3*(-5)(-5)=a_2*(-5)$

and so on.

Then

$a_1=3; a_(n+1)=a_n(-5)$

A geometric sequence is defined by the explicit formula a_n = 3(-5)^(n-1)a_n = 3(-5)^(n-1), what is the recursive formula for the nth term of this sequence?