Question

A golf ball of mass 200 g, initially at rest, is hit by a club. After the impact, the ball moves with a velocity of 45.0 m/s east. If the ball and club were in contact for 0.05 seconds, what is the average force acting on the ball?

Steps please

Answer 1

Average acceleration = change in velocity/time taken for the change

Here, the ball was initially at rest,then gained a velocity of `45 m/s`

So,change in velocity `45-0=45 m/s`

So,average acceleration(`a`) = `45/0.05= 900 m/s^2`

So,average force acted on the ball was `m×a=(500/1000)×900 N =450N`