# A great white shark swims 22 feet below sea level. If the shark is 67.7 feet from the sailboat, what is the angle of depression of the boat to the shark?

Jun 9, 2018

${18}^{\circ} \text{to the nearest degree}$

#### Explanation:

$\cot \theta = \frac{a \mathrm{dj} a c e n t}{o p p o s i t e} = \frac{67.6}{22} = 3.072727273$

$\therefore \theta = {18}^{\circ} 01 ' 38 ' ' = \text{angle of depression}$

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check:-

$\therefore \frac{o p p o s i t e}{a \mathrm{dj} a c e n t} = \tan \theta$

$\therefore o p p o s i t e = \tan \theta \times a \mathrm{dj} a c e n t$

$\therefore o p p o s i t e = \tan {18}^{\circ} 01 ' 38 ' ' \times 67.6 = 22 f t$