A hemispherical water tank has an inside diameter of 10 feet. If water has a density of 62.4 pounds per cubic foot, what is the weight of the water in a full tank, to the nearest pound?

1 Answer
Solace M.
Jun 2, 2017

16,336 pounds

Explanation:

First we find out what the equation of a sphere's volume is,
#4/3 pi r^3#, and then we half the equation because a hemisphere is a sphere cut in half. Thus, the equation becomes #2/3 pi r^3#. Next we plug in the numbers for the equation. Since our diameter is 10, and the radius is the diameter divided by 2, the radius is 5. We substitutes #r# for 5 in the hemisphere equation to get Volume #= 261.799# cubic feet. The last step is to multiply the volume with the density of the water, so we get #261.799*62.4 ~~ 16,336# pounds of water in that tank, to the nearest foot.

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