# A hiker travels 300 m [N], turns around and hikes 550 m [S], and then hikes back another 50.0 m[N]. He manages to do this in 7200 seconds. What is the hiker's displacement? What is the hiker's average speed? What is the hiker's velocity?

##### 1 Answer

#### Answer:

Displacement: **200 m**

Average speed: **0.125 m/s**

Average velocity: **0.0278 m/s**

#### Explanation:

Let's start with the hiker's displacemnt, which is simply the distance between its **starting point** and its **finish point**.

Displacement *does not* take into account the path taken from start to finish, it just deals with the *shortest* distance between these two points.

So, you know that your hiker first travels **300 m** north, then turns around and hikes **550 m** south.

At this point, he will be **250 m** south of his starting point, since hiking 300 m south would have taken him right back to his starting point.

After this, he walks **50 m** north again, *towards* the starting point.

This means that the distance between the starting point and the finish point will be equal to **200 m**. The hiker's displacement will thus be

Now for his average speed. Average speed is defined as the *total distance* covered by the hiker divided by the time total time needed to cover this distance.

The total distance covered by the hiker will be

This means that his average speed was

*Velocity* is actually a vector quantity, so you need to determine both the *magnitude* and the *direction* of the vector.

Because your hiker changes direction, you can't have a **constant** velocity. This means that you have to use *average velocity*, which, for straight line motions, is simply the ratio between the displacement of the hiker and the total time of the motion.