Question

A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 657 m/s. The gun is pointed directly at the center of the bull's-eye......?

A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 657 m/s. The gun is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.020 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

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Answer 1

`"please have a look at the solution below."`

Explanation:

• friction and air resistance are ignored.
• The bullet has done a freely falling motion from the point B to the point C..

`BC=y=1/2 g t^2`

`0.02=1/2*9.81*t^2`

`t^2=(2*0.02)/(9.81)`

`t^2=(0.04)/(9.81)`

`sqrt(t^2)=sqrt((0.04)/(9.81))`

• the flying time of the bullet is:

`t=0.02" "sec`

`AB=v*t`

`AB=657*0.02=13.14" "meters.`