A) How to calculate the theoretical yield of water resulting from the complete combustion of 1.60 g of methane b) When the reaction was run in the lab 3.30 g of water were formed. What is the percent yield of water for this run? CH4 + 2 O2 ->CO2 + 2 H2O?
Once again, start with the balanced chemical equation for the combustion of methane,
You have a
The theoretical yield is the yield you'd get for a 100% reaction - i.e. when all the methane reacted and water was produced according to the aforementioned mole ratio. So, in theory, this reaction would produce
Now, the experiment you ran produced
The reaction's percent yield for water will be