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A hyperbola's center is at (1,-3). a^2 is 4 and b^2 is 16. How would I know if the hyperbola is horizontal or vertical? Can't it be both?

1 Answer

May 21, 2018

Yes, the given information does not allow to determine whether the form is horizontal or vertical, therefore, it is both.

Explanation:

The horizontal transverse axis form is:

$\frac{{(x - 1)}^{2}}{4} - \frac{{(y - - 3)}^{2}}{16} = 1$ $(x-1)^2/4-(y--3)^2/16=1$

The vertical transverse axis form is:

$\frac{{(y - - 3)}^{2}}{4} - \frac{{(x - 1)}^{2}}{16} = 1$ $(y--3)^2/4-(x-1)^2/16=1$

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