Take #v_1# as 4.7m/s
#t_1# = 3.3m
Use this equation to calculate the distance
#v_1xx t_1 = d/cancel(t)*cancel(t_1)#
#v_1 xx t_1 = d#
Where dis distance
t is time
v is velocity
Plug in the variables
3.3min must be converted to secs
#3.3cancel(min) xx (60sec)/cancel(min) = 198sec#
#(4.7m)/cancel(sec) xx 198cancel(sec) = 930.6m = d_1#
Do the same for #v_2# that is the another velocity
= #(5.8m)/sec xx (4.4min xx (60sec)/(1cancel(min)))#
= #(5.8m)/cancel(sec) xx 264cancel(sec) =1531.2m = d_2#
#(Deltad)/(Deltat) = "average velocity"#
#Deltad = d_1 + d_2 = 930.6m + 1531.2m = 2461.8#
#Deltat = t_1 + t_2 = 198sec + 264sec= 462sec#
#(Deltad)/(Deltat) = (2461.8m)/(462sec) = 5.32857142857/sec#
#5.32857142857/sec) = color(red)("average velocity")#