A jumbo jet must reach a speed of 360 km/h on the runway for takeoff. What is the least constant acceleration needed for takeoff from a 1.80 km runway?

1 Answer
Harish Chandra Rajpoot
Jul 2, 2018

#2.777\ m/s^2#

Explanation:

The least acceleration #a# of jumbo jet starting from rest #u=0# to reach a velocity of #v=360\ \text{km/hr}=100\ m/s# running on runway of #s=1.8\ km=1800\ m# to take off is given by third equation of motion

#v^2=u^2+2as#

#100^2=0^2+2a(1800)#

#a=\frac{10000}{3600}#

#a=2.7777\ m/s^2#

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