Question

A lab has 20% acid solution and a 50% acid solution. How many liters of each are required to obtain 600 liters of a 30% acid solution?

Answer 1

I guess Acid A and Acid B (not 20% acid solution or 50% acid solution). The first (400 liters) and the second (200 liters)

Explanation:

The equation is
`(0.2*A)+(0.5*(600-A))=0.3*600`
`(0.2*A)-(0.5*A)=-300+180`
`0.3*A=120`
`A=400` Therefore Acid A take 400 liters.

The rest (200 liters) is Acid B. Final volume will be 600 liters and 30%.