# A lab has 20% acid solution and a 50% acid solution. How many liters of each are required to obtain 600 liters of a 30% acid solution?

Apr 4, 2017

I guess Acid A and Acid B (not 20% acid solution or 50% acid solution). The first (400 liters) and the second (200 liters)

#### Explanation:

The equation is
$\left(0.2 \cdot A\right) + \left(0.5 \cdot \left(600 - A\right)\right) = 0.3 \cdot 600$
$\left(0.2 \cdot A\right) - \left(0.5 \cdot A\right) = - 300 + 180$
$0.3 \cdot A = 120$
$A = 400$ Therefore Acid A take 400 liters.

The rest (200 liters) is Acid B. Final volume will be 600 liters and 30%.