Question

A lab is growing bacteria in a culture dish. The amount of bacteria in the dish doubles every 3 hours. Initially, there are 500 bacteria in the dish. How many are in the dish after 9 hours?

Answer 1

`I(n)=I(2)^(n/t)`

Explanation:

I = initial amount
n = time passed
T = period of doubling
2 = an abstract number. It could be 3 if it's tripling

Plug in the numbers:

`I(9)=500(2)^(9/3)`

`I(9)=4000`