A large city is growing by at rate of 0.8% annually. If there were 3,390,000 residents of the city in 1992, predict how many will be living in the city in 1997?

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Answer 1 · 2016-07-15T13:52:15

4981022

so the population increase in year one is
# p_1 = p_0*1.08#
then in year two
# p_2 = p1*1.08# or #(p_0*1.08)*1.08#

continuing the pattern

# p_n = p_0*1.08^n#

now plugging in and solving

# p_0 = 3390000, n =1997-1992=5#

# p_5 = 3390000*1.08^5#

# p_5 ~~ 4981022#