A lightbulb contains Ar gas at a temperature of 295K and at a pressure of 75kPa. The light bulb is switched on, and after 30 minutes its temperature is 418 K. What is a numerical setup for calculating the pressure of the gas inside the light bulb at 418K?

Assume the volume of the light bulb remains constant.

1 Answer
May 9, 2017

Answer:

The assumption is quite reasonable.........

Explanation:

#P_1/T_1=P_2/T_2# given constant #n#, and constant #V#, conditions that certainly obtain with a fixed volume light bulb.

And so #P_2=P_1/T_1xxT_2#

#=(75*kPa)/(295*cancelK)xx418*cancelK#

#~=100*kPa#.

Had the light bulb been sealed at normal pressure during its manufacture, what do you think might occur when it is operated?