A line has a slope of #5#. It passes through the points #(1,4)# and #(6, y)#. What is the value of #y#?

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Answer 1 · 2016-03-20T18:38:36

#y=29#

We are going to use the fact that when a line passes through two points : #(x_1,y_1)# and #(x_2,y_2)#

the slope is given by the following formula:

Slope #=(Deltay)/(Deltax) = (y_2-y_1)/(x_2-x_1)#

In the present case, the slope is #5# and the points are #(1,4)# and #(6,y)#

Hence,

#5=(y-4)/(6-1)#

Next, solve the above equation for #y#

#rarr 5*(6-1)=y-4#

#rarr 5*(5)=y-4#

#rarr 25=y-4#

#rarr 25+4=y-4+4#

#rarr 29=y#

#rarr color(blue)(y=29)#