A line segment has endpoints at #(4 ,7 )# and #(1 ,5 )#. The line segment is dilated by a factor of #4 # around #(3 ,3 )#. What are the new endpoints and length of the line segment?

1 Answer
Dec 31, 2017

New endpoints: #color(green)(""(-5,8))# and #color(blue)(""(7,16))#
New line segment length: #sqrt(265#

Explanation:

Dilation about a center means that all points are moved so that the distance from the center is increased by the dilation factor along the same vector.
By saying "along the same vector" we mean that the slope: #(deltay):(deltax)# remains constant.

In this example the center is at #color(red)(""(3,3))# so #(deltay):(deltax)# to the point #color(blue)(""(4,7))# is #1:4#
scaling this up by the dilation factor of #4#
gives a new offset from the center of #4xx(vec(1:4))=(vec(4:16))#
for a resulting location:
#color(white)("XXX")color(red)(""(3,3))+(vec(4,16))=color(blue)(""(7,19))#

Similarly, we can determine the dilated location of #color(green)(""(1,5))# as #color(green)(""(-5,8))#

and the length of the dilated line segment is simply the distance between the dilated endpoints #color(blue)(""(7,19))# and #color(green)(""(-5,8))# as determined by the Pythagorean theorem:
#sqrt((7-(-5))^2+(19-8)^2)=sqrt(12^2+11^2)=sqrt(265)~~16.28#
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