A line segment has endpoints at (8 , 4) and (1 , 2). If the line segment is rotated about the origin by (pi)/2 , translated vertically by 4, and reflected about the x-axis, what will the line segment's new endpoints be?

1 Answer
May 22, 2018

(4,-12) and (2,-5)

Explanation:

You have not specified the direction of the rotation, so I will take this as being counter clockwise. If we look at each transformation and translation in order we get the following:

A rotation of pi/2 anticlockwise will map:

(x,y)->(-y,x)

This result takes a little thought. The easiest way to see this is, to think not of rotating a point, but rotating the axes themselves. If we rotate the axes pi/2 counterclockwise, the positive x axis becomes the positive y axis and the positive y axis becomes the negative x axis.

A translation of 4 units vertically maps:

(x,y)->(x,y+4)

A reflection in the x axis maps:

(x,y)->(x,-y)

This is the same as reflecting the axes, so positive y becomes negative y and x remains unchanged.

Putting these together in order:

(x,y)->(-y,x)->(-y,x+4)->(y,-(x+4))

Naming endpoints A and B:

A=(8,4)

B=(1,2)

A=(8,4)->(y,-(x+4))=(4,-12)

B=(1,2)->(y,-(x+4))=(2,-5)