A line segment is bisected by a line with the equation # - 3 y + 6 x = 5 #. If one end of the line segment is at #( 3 , 3 )#, where is the other end?
The other end will be any point on the line
To find one point that satisfy the required conditions, we could take the horizontal line through
The point horizontally
The bisector line,
Furthermore any point,
will provide an endpoint that meets the requirement.
So the required line will have a slope of
Using the slope-point form and then manipulating the derived equation into a similar form to that of the bisector line,