A machine moves a 600 N object 6 meters. If the amount of work put into the machine is 4500 J, what is the efficiency of the machine?
1 Answer
Apr 7, 2018
Explanation:
Work done to move a
#"W"_"out" = "600 N × 6 m = 3600 J"#
Efficiency
#eta = ("W"_"out")/("W"_"in") × 100% = "3600 J"/"4500 J" = 80%#
