# A man reached a speed of 372 km/h on his motorcycle. Suppose the man drives off a horizontal ramp at this speed and lands a horizontal distance of 40.0 m away from the edge of the ramp. What is the height of the ramp, neglecting air resistance?

Nov 26, 2015

$0.73 \text{m}$

#### Explanation:

First we need to convert the speed into $\text{m/s}$:

$v = \frac{372 \times 1000}{60 \times 60} = 103.3 \text{m/s}$

The horizontal component of velocity is constant so we can say:

Time = distance/speed = $\frac{40}{103.3} = 0.39 \text{s}$

To get the vertical height we can use:

$s = \frac{1}{2} \text{g} {t}^{2}$

$\therefore s = 0.5 \times 9.8 \times {0.39}^{2}$

$s = 0.73 \text{m}$