Question

A man's age is 36 and his daughter is 3 years. In how many years will the man be 4 times as old as his daughter?

Answer 1

This will be in `8` years.

Explanation:

To calculate first we have to write an equation. Now we know that:

Man is `36` years old,

Daughter is `3` years old.

If we write that `n` is the number of years in which the man will be `4` times older than the girls we have:

Man's age: `36+n`

Daughter's age: `3+n`

Man is said to be `4` times older than the girl. That leads to an equation:

`36+n=4xx(3+n)`

`36+n=12+4n`

`3n=24`

`n=8`

We can check the solution:

Now man is `36` years old, daughter is `3` years old. In `8` years the man will be `44`, and the girl `11`. So the answer is correct. In `8` years the mabn will be `4` times older than his daughter.