A mass launched at 30 degrees to horizontal within initial speed 25m/s what is the maximum height obtained and after what time does the mass move a horizontal distance of 3m?

1 Answer
Jane
Mar 3, 2018

#7.96 m#

#0.14s#

Explanation:

maximum height for a projectile motion is given as, #H= (u^2 sin^2 theta)/(2g)# (where, #u# is the velocity of projection at an angle #theta# w.r.t the horizontal)[derivation of the formula is shown in the diagram below]

so, #H=7.96 m#

Now,the horizontal velocity of the mass is #u cos theta# which remains constant through out,so if it goes #3 m# horizontally in time #t#,we can say,

#3=25 cos 30 *t#

so, #t=0.14s#enter image source here

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