Question

A meatball is launched off the table horizontally at 3.2 m/s. What is its vertical and horizontal speed after 3.2 seconds?

Answer 1

horizontal speed remains constant through out the motion ,it is `3.2 ms^-1`

Suppose,after `3.2 s` its vertical component of velocity will be `V`,so we can use the formula `V=u+g t`

here,initial component of downward velocity was zero `(u=0)`

So, `V=9.8*3.2=31.36ms^-1`