Question

A mole of gas at O°C and 760mmHg occupies 22.41 L. What is the volume at 20°C and 760mmHg?

Answer 1

We use Charles' Law to give `V~=24*L`

Explanation:

At constant pressure `VpropT` or `V=kT`.

Thus (solving for `k`), `V_1/T_1=V_2/T_2`, and `V_2=V_1/T_1xxT_2`. Of course, `T` must be in terms of absolute temperature.

`V_2` `=` `(22.41*L)/(273.15*K)xx293.15*K` `=??L`

Is the slight increase in volume consistent with a temperature increase?