A parallel-plate capacitor has a capacitance of 1.35 pF. If a 12.0 V battery is connected to this capacitor, how much electrical potential energy would it store?

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Answer 1 · 2016-05-25T17:44:33

#E_p=9.72*10^(-11)J#

#c=1.35" " p F=1.35*10^(-12) F#

#V=12V#

#E_p=1/2*C*V^2#

#E_p=1/2*1.35*10^(-12*12^2)#

#E_p=1/2*1.35*10^(-12)*144#

#E_p=72*1.35*10^(-12)#

#E_p=97.2*10^(-12)#

#E_p=9.72*10^(-11)J#