Question

A particle is going following an equation of a=20t-6t^2 (a in m/s^2) Find when will it have the maximum acceleration value?

Answer 1

`1.67 s`

Explanation:

Given, `a=20t-6t^2`

So, acceleration will be maximum when rate of change in acceleration will be zero.

So, `(da)/(dt) = 20-12t=0`

or, `t=1.67`