A particle is projected from ground with speed 80m/s at an angle 30° with horizontal from ground.What is the magnitude of average velocity of particle in time interval t=2s to t=6s?
1 Answer
Mar 18, 2018
Let's see the time taken by the particle to reach maximum height,it is,
Given,
so,
That means at
So,upward displacement in
and displacement in
So,vertical dispacement in
And horizontal displacement in
So,net displacement is
So,average velcoity = total displacement /total time=