A particle is projected upwards with velocity 60m/s. what will be the pathlenght after 8 second?

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Answer 1 · 2018-03-21T02:05:50

#"200 m"#

Time taken to reach maximum height is

#"T" = "u"/"g" = "60 m/s"/("10 m/s"^2) = "6 s"#

So, It takes #6# seconds to reach maximum height and in next #2# seconds it travel downwards.

Maximum height #= ("u"^2)/("2g") = ("60 m/s")^2/(2 × "10 m/s"^2) = color(blue)"180 m"#

Distance travelled in next #"2 s"# is

#"S" = "ut" + 1/2\ "at"^2#

#"S" = ("0 m/s" × "2 s") + (1/2 × "10 m/s"^2 × ("2 s")^2) = color(blue)"20 m"#

Path length #"= 180 m + 20 m = 200 m"#