A particle is projected upwards with velocity 60m/s. what will be the pathlenght after 8 second?

1 Answer
Mar 21, 2018

"200 m"

Explanation:

Time taken to reach maximum height is

"T" = "u"/"g" = "60 m/s"/("10 m/s"^2) = "6 s"

So, It takes 6 seconds to reach maximum height and in next 2 seconds it travel downwards.

Maximum height = ("u"^2)/("2g") = ("60 m/s")^2/(2 × "10 m/s"^2) = color(blue)"180 m"

Distance travelled in next "2 s" is

"S" = "ut" + 1/2\ "at"^2

"S" = ("0 m/s" × "2 s") + (1/2 × "10 m/s"^2 × ("2 s")^2) = color(blue)"20 m"

Path length "= 180 m + 20 m = 200 m"