A particle's acceleration along a straight line is given by #a(t)=48t^2+2t+6# . It's initial velocity is equal to -3cm/s and its initial position is 1 cm. Find its position function s(t). Answer is #s(t)=4t^4+1/3t^3+3t^2-3t+1# but I can't it figure out?
#s(t)=4t^4+1/3t^3+3t^2-3t+1#
1 Answer
Apr 30, 2018
Explanation: