Question

A pelican flying at 7.6 m/s along a horizontal path drops a fish from a height of 2.7 m above the water. How far does the fish travel horizontally before hitting the water below?

Answer 1

`5.64"m"`

Explanation:

Get the time of flight first by considering the vertical component of motion:

`s=1/2"g"t^2`

`:.t=sqrt((2xx2.7)/9.8)`

`t=0.742"s"`

Now we consider the horizontal component of the motion:

`s=vxxt=7.6xx0.742=5.64"m"`