A pendulum with a period of 1.8 s on earth is moved to another planet, on the new planet it's period is2.5 s. What is the gravitational acceleration of this planet?

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Answer 1 · 2017-05-14T09:58:38

The gravitational acceleration is #=5.08ms^-2#

The period of a pendulum is

#T=2pisqrt(l/g)#

length of the pendulum is #l#

on earth, #g=9.8ms^-2#

#1.8=2pisqrt(l/9.8)#

#2pisqrtl=1.8sqrt9.8#

On the other planet

#T=2.5=2pisqrt(l/g_1)#

So,

#sqrtg_1=(2pisqrtl)/2.5=(1.8sqrt9.8)/2.5#

#g_1=(1.8/2.5)^2*9.8#

#=5.08ms^-2#