A pharmacist has one solution that is 40% iodine and 60% water, and another solution that is 3% iodine. How many liters of each solution should the pharmacist use to make 11 liters of a solution that is 19% iodine?

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Answer 1 · 2017-08-28T09:16:27

The volume of #40%# iodine solution is #=4.76L# and the volume of the #3%# iodine solution is #=6.243L#

Let the volume of the solution #40%# iodine be #=x L #

Then, the volume of the solution #3%# iodine be #=(11-x)L#

The material balance with respect to iodine is

#x*0.4+(11-x)*0.03=11*0.19#

#0.4x+0.33-0.03x=2.09#

#0.37x=2.09-0.33=1.76#

#x=1.76/0.37=4.757L#