Question

A photon and electron have got same de borglie wavelength prove that the energy of photon is 2mclamda/h of the kinetic energy of electron??

Answer 1

See below

Explanation:

From DeBroglie:

• `lambda_e = h/p [= lambda_gamma]`

`implies T_e = p^2/(2m) = (h /lambda)^2/(2m) = h^2/(2m lambda^2)`

`E_gamma/T_e = ((hc)/lambda)/(h^2/(2m lambda^2))`

`= (2 m c lambda )/(h)`