A plane is traveling 200 m/s in one direction. Meanwhile, another plane is traveling the opposite direction at 550 m/s. How long will it take for the planes to travel the same distance of 7600 m?

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Answer 1 · 2018-03-09T18:09:32

The faster plane: # 13.8 s#.

The slower plane: #38 s#.

The faster plane will travel 7600 m in #(7600 m)/(550 m/s) = 13.8 s#.

The slower plane will travel 7600 m in #(7600 m)/(200 m/s) = 38 s#.

I hope this helps,
Steve

Answer 2 · 2018-03-10T01:54:23

Well, it'll take the slower one #38# seconds but only #~~13.8# seconds for the fast one.

We need to use the distance equation and rearrange it for time here, which states that

#d=s*t#

Rearranging for #t#, we get

#t=d/s#

So, for the faster one, it'll take

#t=(7600color(red)cancelcolor(black)"m")/(200color(red)cancelcolor(black)"m""/s")=38 \ "s"#

For the slower one, it'll take

#t=(7600color(red)cancelcolor(black)"m")/(550color(red)cancelcolor(black)"m""/s")~~13.8 \ "s"#

Hope this helps!