# A projectile is shot at a velocity of # 2 m/s# and an angle of #pi/4 #. What is the projectile's peak height?

##### 1 Answer

#### Explanation:

You have a projectile and you want to know the vertical position (i.e., the

You are given

#v_0=2# m/s (pretty slow, about 4.5 mph)#theta_0=pi"/"4# #g=9.8# m/s#""^2#

Plugging in those values we get

A graphing calculator will find your max height at

graph{y=2sin(pi/4)x-0.5(9.8)x^2[-.01,.3,-.01,.11]}

The time at which the this function is maximum is discovered by solving for

Set

Now solve for

So the maximum height occurs at that time