A projectile is shot at a velocity of # 2 m/s# and an angle of #pi/4 #. What is the projectile's peak height?
1 Answer
Explanation:
You have a projectile and you want to know the vertical position (i.e., the
You are given
#v_0=2# m/s (pretty slow, about 4.5 mph)#theta_0=pi"/"4# #g=9.8# m/s#""^2#
Plugging in those values we get
A graphing calculator will find your max height at
graph{y=2sin(pi/4)x-0.5(9.8)x^2[-.01,.3,-.01,.11]}
The time at which the this function is maximum is discovered by solving for
Set
Now solve for
So the maximum height occurs at that time