A projectile is shot at a velocity of # 35 m/s# and an angle of #pi/6 #. What is the projectile's peak height?
See this URL https://en.m.wikipedia.org/wiki/Projectile_motion
Equation for the peak height is
This is derived using the fundamental equations of motion and the assumption that the trajectory is parabolic. The objects vertical velocity at the peak height is zero m/s.
v = 35 m/s
Theta =30 degrees
g=9.8m/s^2 Gravitational acceleration