# A projectile is shot at a velocity of # 35 m/s# and an angle of #pi/6 #. What is the projectile's peak height?

##### 1 Answer

Feb 2, 2016

15.6 m

#### Explanation:

See this URL https://en.m.wikipedia.org/wiki/Projectile_motion

Equation for the peak height is

H =

This is derived using the fundamental equations of motion and the assumption that the trajectory is parabolic. The objects vertical velocity at the peak height is zero m/s.

v = 35 m/s

Theta =30 degrees

g=9.8m/s^2 Gravitational acceleration