A projectile is shot at an angle of (5pi)/12  and a velocity of  1 m/s. How far away will the projectile land?

Range of projectile motion is expressed as $\left({u}^{2} \sin \frac{2 \theta}{g}\right)$
Where $u$ is the velocity of projection and $\theta$ is the angle of projection.
Given, $v = 1 m \text{/} s$ and $\theta = \frac{5 \pi}{12}$
So, putting in the values, we get the range is $0.05 m$.