A projectile is shot at an angle of #pi/12 # and a velocity of # 13 m/s#. How far away will the projectile land?

1 Answer
Apr 19, 2017

The distance is #=8.62m#

Explanation:

Resolving in the vertical direction #uarr^+#

initial velocity is #u_y=vsintheta=13*sin(1/12pi)#

Acceleration is #a=-g#

At the maximum height, #v=0#

We apply the equation of motion

#v=u+at#

to calculate the time to reach the greatest height

#0=13sin(1/12pi)-g*t#

#t=13/g*sin(1/12pi)#

#=0.34s#

Resolving in the horizontal direction #rarr^+#

To find the distance where the projectile will land, we apply the equation of motion

#s=u_x*2t#

#=13cos(1/4pi)*0.34*2#

#=8.62m#