# A projectile is shot at an angle of pi/12  and a velocity of 31 m/s. How far away will the projectile land?

Oct 15, 2016

$\approx 50 m$

#### Explanation:

For projectile motion over flat ground the range $R$ is

$R = {v}^{2} / g \sin 2 \theta$

Here that means

$R = {31}^{2} / 9.81 \sin \left(\frac{\pi}{6}\right) \approx 50 m$