A projectile is shot at an angle of #pi/12 # and a velocity of #45 m/s#. How far away will the projectile land?

1 Answer
Jan 11, 2016

Range#=103.316m#

Explanation:

The range of a projectile is given by
#R=(v_0^2*Sin2theta)/g#

Where #R# is the range, #v_0# is the initial or muzzle velocity, #theta# is the throwing angle and #g# is the acceleration due to gravity.
Here #v_0=45m/s#, #theta=pi/12#, #g=9.8m/s^2# and #R=??#

#implies R=(45^2*Sin(2*pi/12))/9.8=(2025*Sin(pi/6))/9.8=((2025)0.5)/9.8=103.316 m#
i
#impliesR=103.316m#