A projectile is shot at an angle of pi/12  and a velocity of 52 m/s. How far away will the projectile land?

The projectile lands $165 m$ far.
First of all you have to find the time when the projectile land, so $v t - \frac{1}{2} a {t}^{2} = 0$, so $t = 3 s$. For this equation you consider the vertical component of speed v(y)=vsin15°.
Now you have the time's value and can use it in the orizontal equation $s = v t$, where v=vcos15°.
$s = 55 \frac{m}{s} \cdot 3 s = 165 m$.