A projectile is shot at an angle of pi/3  and a velocity of  24 m/s. How far away will the projectile land?

Feb 7, 2016

${x}_{m} = 50 , 8478 m$

Explanation:

$\theta = \frac{\cancel{\pi}}{3} \cdot \frac{180}{\cancel{\pi}} = {60}^{o}$
${v}_{i x} \text{:x component of initial velocity}$
${t}_{e t} : \text{elapsed time}$
${x}_{m} = {v}_{i x} \cdot {t}_{e t}$
${v}_{i x} = {v}_{i} \cdot \cos \theta$
${v}_{i x} = 24 \cdot 0.5 = 12 \frac{m}{s}$
${t}_{e t} = \frac{2 \cdot {v}_{i} \cdot \sin \theta}{g}$
${t}_{e t} = \frac{2 \cdot 24 \cdot 0 , 866}{9 , 81}$
${t}_{e t} = 4 , 2373088685 s$
${x}_{m} = 12 \cdot 4 , 2373088685$
${x}_{m} = 50 , 8478 m$